Tentukan hasil bagi dari soal berikut 1 2x 7x 14x 40 oleh 2x 52 3x 4x 5x 6 oleh x 2

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Jawab:

1.  x² + 6x + 8   atau   (x+2)(x+4)

2. displaystyle f 3x^2-10x+15-frac{24}{x+2}

Penjelasan dengan langkah-langkah:

Nomor 1

egin{aligned}&   !f x^2+6x+8\2x-5:&overline{smash{)}2x^3+7x^2-14x-40 }\& :!underline{2x^3-5x^2}\&qquad ;12x^2-14x\&qquad ;underline{12x^2-30x}\&qquad ;qquadquad:16x-40\&qquad ;qquadquad:underline{16x-40}\&qquad ;qquadquadqquadquad :0end{aligned}

Kalau mau difaktorkan lagi:

x² + 6x + 8 = (x+2)(x+4)

Nomor 2

egin{aligned}& f 3x^2-10x+15-frac{24}{x+2}\x+2:&overline{smash{)}3x^3-4x^2-  !5x+6qquad }\& :!underline{3x^3+6x^2}\&quad  ;!{-}10x^2-  !5x\&quad  ;!underline{{-}10x^2-20x}\&qquad ;qquadquad:15x+  !6\&qquad ;qquadquad:underline{15x+30}\&qquad ;qquadquadqquad {-24}end{aligned}

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