Jika panjang gelombang cahaya tampak 6000a0 maka frekuensi gelombang tersebut adalah

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Penjelasan:

Diketahui:

lamda = 6000 A° = 6000×10^-10 m

= 6×10^-7m

v = 3×10^8 m/s

ditanya :

f =?

jawab:

f = v/lamda

= 3×10^8 / 6×10^-7

= 0,5 × 10^15

= 5 × 10^14 Hz

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Leave a Reply

Your email address will not be published. Required fields are marked *

Leave a Reply

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Jika panjang gelombang cahaya tampak 6000a0 maka frekuensi gelombang tersebut adalah

Posted on

Penjelasan:

Diketahui:

lamda = 6000 A° = 6000×10^-10 m

= 6×10^-7m

v = 3×10^8 m/s

ditanya :

f =?

jawab:

f = v/lamda

= 3×10^8 / 6×10^-7

= 0,5 × 10^15

= 5 × 10^14 Hz

Leave a Reply

Your email address will not be published. Required fields are marked *

Jika panjang gelombang cahaya tampak 6000a0 maka frekuensi gelombang tersebut adalah

Posted on

Penjelasan:

Diketahui:

lamda = 6000 A° = 6000×10^-10 m

= 6×10^-7m

v = 3×10^8 m/s

ditanya :

f =?

jawab:

f = v/lamda

= 3×10^8 / 6×10^-7

= 0,5 × 10^15

= 5 × 10^14 Hz

Leave a Reply

Your email address will not be published. Required fields are marked *