1 tentukan persamaan garis yang tegak lurus garis dengan persamaan y 3x 4 dan melalui titik K 6 2 bantu jawab kak

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Jawaban:

3y = -x + 12

Penjelasan dengan langkah-langkah:

y = 3x + 4

m1 = 3

karena tegak lurus

m1 × m2 = -1

3 × m2 = -1

m2 = -1/3

persamaan

(y – y1) = m(x – x1)

(y – (-2) = -1/3 (x – 6)

3(y + 2) = -1(x – 6)

3y + 6 = -x + 6

3y = -x + 6 + 6

3y = -x + 12

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1 tentukan persamaan garis yang tegak lurus garis dengan persamaan y 3x 4 dan melalui titik K 6 2 bantu jawab kak

Posted on

Jawaban:

3y = -x + 12

Penjelasan dengan langkah-langkah:

y = 3x + 4

m1 = 3

karena tegak lurus

m1 × m2 = -1

3 × m2 = -1

m2 = -1/3

persamaan

(y – y1) = m(x – x1)

(y – (-2) = -1/3 (x – 6)

3(y + 2) = -1(x – 6)

3y + 6 = -x + 6

3y = -x + 6 + 6

3y = -x + 12

Leave a Reply

Your email address will not be published. Required fields are marked *

Leave a Reply

Your email address will not be published. Required fields are marked *

1 tentukan persamaan garis yang tegak lurus garis dengan persamaan y 3x 4 dan melalui titik K 6 2 bantu jawab kak

Posted on

Jawaban:

3y = -x + 12

Penjelasan dengan langkah-langkah:

y = 3x + 4

m1 = 3

karena tegak lurus

m1 × m2 = -1

3 × m2 = -1

m2 = -1/3

persamaan

(y – y1) = m(x – x1)

(y – (-2) = -1/3 (x – 6)

3(y + 2) = -1(x – 6)

3y + 6 = -x + 6

3y = -x + 6 + 6

3y = -x + 12

Leave a Reply

Your email address will not be published. Required fields are marked *